Watches, Warnings & Advisories



2 products issued by NWS for:

Beach Hazards Statement

Lakeshore Hazard Message
National Weather Service Milwaukee/Sullivan WI
945 PM CDT Wed Jul 16 2025

WIZ052-060-066-071-072-171045-
/O.CON.KMKX.BH.S.0006.250717T0600Z-250718T0600Z/
Sheboygan-Ozaukee-Milwaukee-Racine-Kenosha-
945 PM CDT Wed Jul 16 2025

...BEACH HAZARDS STATEMENT REMAINS IN EFFECT FROM 1 AM CDT
THURSDAY THROUGH LATE THURSDAY NIGHT...

* WHAT...Life threatening waves of 3 to 5 feet and dangerous
  currents are expected.

* WHERE...Sheboygan, Ozaukee, Milwaukee, Racine and Kenosha
  Counties.

* WHEN...Until late Thursday evening.

* IMPACTS...Dangerous swimming conditions are expected due to
  high waves and onshore winds.

PRECAUTIONARY/PREPAREDNESS ACTIONS...

Stay out of the water and away from dangerous areas like piers
and breakwalls.  Strong structural and longshore currents are
expected.  Rip currents are possible.

&&

$$
Wood




Hazardous Weather Outlook

Hazardous Weather Outlook...UPDATED
National Weather Service Milwaukee/Sullivan WI
921 PM CDT Wed Jul 16 2025

WIZ046-047-051-052-056>060-062>072-180230-
Marquette-Green Lake-Fond du Lac-Sheboygan-Sauk-Columbia-Dodge-
Washington-Ozaukee-Iowa-Dane-Jefferson-Waukesha-Milwaukee-
Lafayette-Green-Rock-Walworth-Racine-Kenosha-
921 PM CDT Wed Jul 16 2025

This Hazardous Weather Outlook is for portions of east central
Wisconsin, south central Wisconsin and southeast Wisconsin.

.DAY ONE...Rest of Tonight

A high swim risk is expected for the Lake Michigan beaches from
Sheboygan to Kenosha County. Life threatening waves and currents
are expected. Stay out of the water, and stay away from dangerous
areas like piers and breakwalls.

.DAYS TWO THROUGH SEVEN...Thursday through Wednesday

The high swim risk for the Lake Michigan beaches will linger into
Thursday night.

Additional thunderstorm chances return at times later Friday
night into the weekend. There are small chances for thunderstorms
early next week.

.SPOTTER INFORMATION STATEMENT...

Spotter activation will not be needed.

$$